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Thread: Settle my wrap debate

  1. #1
    Elite (Gold) kapscarper's Avatar
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    Default Settle my wrap debate

    If fishing at 12 wraps in 26 foot of water how many wraps would you clip your spod at?


    Cheers for the input
    Edited for the sensitive prissy meow meows we entertain

  2. #2
    Site Regular Edna Birch's Avatar
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    11
    Are you gonna bark all day, little doggy, or are you gonna bite?

  3. #3
    Frequent User yonny's Avatar
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    11 and a 1/4 for me.

  4. #4
    Moderator sam's Avatar
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    Lets apply good old Pythagoras Theorum and get back to some honest GCSE Maths:

    12 x 4 = 48

    48 x 48 = 2304
    26 x 26 = 676

    2304 - 676 = 1628

    Square root of 1628 = 40.35

    Clip your spod up at 40.35 foot, which is just over 10 wraps.

    **sam**

  5. #5
    Frequent User DanFisher's Avatar
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    Being an engineer, I've just used AutoCAD to get the answer and depending how tall you are and the angle of your rod you will get 2 - 3 foot swing back at that distance in that depth of water. That said, that is using precise distances and not accounting for bouncing off the clip. It also depends how big the spot is and how you like baiting. I would always prefer to bait the back of my spot and fish the front of it so I haven't got line going through the bait, so for me I would clip up at the same distance or take a very small step back with the spod rod!

    Sorry for the incredibly geeky response!

  6. #6
    Frequent User DanFisher's Avatar
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    Quote Originally Posted by sam View Post
    Lets apply good old Pythagoras Theorum and get back to some honest GCSE Maths:

    12 x 4 = 48

    48 x 48 = 2304
    26 x 26 = 676

    2304 - 676 = 1628

    Square root of 1628 = 40.35

    Clip your spod up at 40.35 foot, which is just over 10 wraps.

    **sam**
    Sorry Sam, but you've done your distance in yards and your depth in feet.

  7. #7
    Elite (Bronze) carphooker's Avatar
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    had a little think and i'd be happy spodding around 11 wraps

  8. #8
    Moderator sam's Avatar
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    Quote Originally Posted by DanFisher View Post
    Sorry Sam, but you've done your distance in yards and your depth in feet.
    You're right! That makes it 36864-676=36188

    Divided by 4 then 4 again leaves 11.88.

    Near as negligible.

    It's been a long morning. Running some complex pivot charts at the moment to find some patterns in some data, so stuck in Excel world.

    Any chance you can share an autocad screen dump of your model?

    **sam**

  9. #9
    Elite (Gold) kapscarper's Avatar
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    So is the genera consensus to wrap at the same or 11
    Edited for the sensitive prissy meow meows we entertain

  10. #10
    Frequent User DanFisher's Avatar
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    Quote Originally Posted by sam View Post
    You're right! That makes it 36864-676=36188

    Divided by 4 then 4 again leaves 11.88.

    Near as negligible.

    It's been a long morning. Running some complex pivot charts at the moment to find some patterns in some data, so stuck in Excel world.

    Any chance you can share an autocad screen dump of your model?

    **sam**
    There you go. Hope that works ok.

    Wraps.jpg
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  11. #11
    Elite (Silver) Nat's Avatar
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    17.3 wraps

    12 x 12/n = 144
    144/26 + n~ = 6

    6X6(F)=36 - 26 = 10 - 12/2 = 17.3 wraps
    <>< "A good angler can tell good stories....." ><>

  12. #12
    Elite (Silver) Nat's Avatar
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    Or just 12 wraps and use the RBT (Random Baiting Technique) then skin up and chill.
    <>< "A good angler can tell good stories....." ><>

  13. #13
    Elite (Bronze) carphooker's Avatar
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    Quote Originally Posted by Nat View Post
    Or just 12 wraps and use the RBT (Random Baiting Technique) then skin up and chill.
    made me laugh , nice one !

  14. #14

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    Quote Originally Posted by kapscarper View Post
    If fishing at 12 wraps in 26 foot of water how many wraps would you clip your spod at?


    Cheers for the input
    Is there wind, a heavy chop on the water? What kind of bait is being cast, fast or slow sinking?

    Generally, set the spod clip at 12 wraps.

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